Rajasthan Board RBSE Class 12 Maths Chapter 12 Differential Equation Ex 12.7
Solve the following differential equations :
Question 1.
Solution:
h and k are such that
3h + 2k – 5 = 0 and 2h + 3k – 5 = 0
Putting these values in equation
h = 1 ,k = 1
This is homogeneous equation
Question 2.
Solution:
Question 3.
(2x + y + 1) dx + (4x + 2y – 1) dy = 0
Solution:
(2x + y + 1) dx + (4x + 2y – 1) dy = 0
Question 4.
Solution:
∴ Integrating
x + C = – 2v – 2 log (1 – v)
or x + C + 2(x + y) + 2 log (1 – x – y) = 0
[∵ v = x + y]
or 3x + 2y + 2 log (1 – x – y) + C = 0,
This is required solution.
Question 5.
Solution:
