RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 5 |
| Subject | Maths |
| Chapter | Chapter 7 |
| Chapter Name | Equivalent Fractions |
| Exercise | Additional Questions |
| Number of Questions | 25 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions
Multiple Choice Questions
Question 1.
Value of numerator in fraction \(\frac { 3 }{ 4 } \)
(a) 1
(b) 2
(c) 3
(d) 4
Question 2.
Value of denominator in fraction \(\frac { 7 }{ 8 } \)
(a) 7
(b) 8
(c) 15
(d) 56
Question 3.
Equivalent fraction of fraction \(\frac { 4 }{ 5 } \)
(a) \(\frac { 4 }{ 20 } \)
(b) \(\frac { 8 }{ 10 } \)
(c) \(\frac { 4 }{ 15 } \)
(d) \(\frac { 8 }{ 20 } \)
Question 4.
Simplest form of \(\frac { 24 }{ 30 } \) is-
(a) \(\frac { 4 }{ 5 } \)
(b) \(\frac { 3 }{ 5 } \)
(c) \(\frac { 5 }{ 4 } \)
(d) \(\frac { 5 }{ 3 } \)
Question 5.
2 \(\frac { 1 }{ 2 } \) read as –
(a) Half
(b) One and half
(c) One and Quarter
(d) Two and half
Question 6.
Equivalent fraction(RBSESolutions.com)of \(\frac { 3 }{ 7 } \)
(a) \(\frac { 3 }{ 14 } \)
(b) \(\frac { 9 }{ 7 } \)
(c) \(\frac { 6 }{ 14 } \)
(d) \(\frac { 10 }{ 14 } \)
Question 7.
1 \(\frac { 1 }{ 4 } \) reads as –
(a) one quarter
(b) one and quarter
(c) one and half
(d) three by four
Question 8.
Value of numerator and(RBSESolutions.com)denominator in fraction \(\frac { 11 }{ 13 } \) –
(a) Numerator 13 denominator 0
(b) Numerator 13 denominator 11
(c) Numerator 11 denominator 13
(d) Numerator 1 denominator 3
Answers
1. (c)
2. (b)
3. (b)
4. (a)
5. (d)
6. (c)
7. (b)
8. (c).
Fill in the blanks in the following Questions
1. Five by seven can be written as fractional form ………………
2. Fractions which are equal called ……………… fraction.
3. To obtain equivalent(RBSESolutions.com)fraction of a fraction, the numerator and denominator of the fraction are multiplied by ……………… number.
4. One of the equivalent fraction of \(\frac { 1 }{ 2 } \) is ………………
5. Number written in the form of ……………… and ……………… called fraction.
Answers
1. \(\frac { 5 }{ 7 } \)
2. Equivalent
3. Same
4. \(\frac { 2 }{ 4 } \)
5. Numerator, Denominator.
Very Short Answer Type Questions
Question 1.
Which are called equivalent fractions ?
Solution.
Fractions which have the same value, are said to be equivalent fractions.
Question 2.
What can be done to obtain equivalent fraction of a fraction.
Solution.
Multiply the numerator(RBSESolutions.com)and denominator of the fraction by same number.
Question 3.
Write three equivalent fractions \(\frac { 3 }{ 5 } \)
Solution.
\(\frac { 6 }{ 10 } \) , \(\frac { 9 }{ 15 } \) , \(\frac { 12 }{ 20 } \)
Question 4.
Write in simplest form.
Solution.
\(\frac { 4 }{ 5 } \)
Short Answer and Essay Type Questions
Question 1.
Write three equivalent fractions each of the following fraction
(1) \(\frac { 2 }{ 3 } \) = ………….. , ………….. , …………..
(2) \(\frac { 1 }{ 7 } \) = ………….. , ………….. , …………..
Solution.
Question 2.
Write four equivalent fractions of \(\frac { 9 }{ 10 } \).
Solution.
(i) \(\frac { 9 }{ 10 } \) × \(\frac { 2 }{ 2 } \) = \(\frac { 18 }{ 20 } \)
(ii) \(\frac { 9 }{ 10 } \) × \(\frac { 3 }{ 3 } \) = \(\frac { 27 }{ 30 } \)
(iii) \(\frac { 9 }{ 10 } \) × \(\frac { 4 }{ 4 } \) = \(\frac { 36 }{ 40 } \)
(iv) \(\frac { 9 }{ 10 } \) × \(\frac { 5 }{ 5 } \) = \(\frac { 45 }{ 50 } \)
Therefore, four equivalent fractions of
\(\frac { 9 }{ 10 } \) = \(\frac { 18 }{ 20 } \) , \(\frac { 27 }{ 30 } \) , \(\frac { 36 }{ 40 } \) and \(\frac { 45 }{ 50 } \)
Question 3.
Give some more examples where we(RBSESolutions.com)get \(\frac { 1 }{ 4 } \) chapati after dividing equally and write down below.
\(\frac { 1 }{ 4 } \) = \(\frac { 2 }{ 8 } \) = \(\frac { 3 }{ 12 } \) = ………….
Solution.
\(\frac { 4 }{ 16 } \) = \(\frac { 5 }{ 20 } \) = \(\frac { 6 }{ 24 } \) = \(\frac { 7 }{ 28 } \) = \(\frac { 8 }{ 32 } \) = …………. etc.
Question 4.
Shade the region of each figure representing fraction given below :
Solution.
Question 5.
Seema bought 5 meter long ribbon from market, if she equally divides it between 4 friends, then what is the length of ribbon each friend will get ?
Solution.
Each friend will get = 5 ÷ 4
= \(\frac { 5 }{ 4 } \) = 1 \(\frac { 1 }{ 4 } \) meter
Therefore each friend(RBSESolutions.com)will get 1 \(\frac { 1 }{ 4 } \)
(One and one by four) meter ribbon.
Question 6.
5 kg. Jaggary divided equally among two families then how much jaggary each family will get ?
Solution.
Each family will get = 5 ÷ 2 = \(\frac { 5 }{ 2 } \) = 2 \(\frac { 1 }{ 2 } \) kg.
Therefore, each family will get 2 \(\frac { 1 }{ 2 } \) (Two and half) kg. Jaggary
Question 7.
6 litre milk distributed between 12 children, then much litre milk each children will drink ?
Solution.
Each children will drink
= 6 ÷ 12 = \(\frac { 6 }{ 12 } \) = \(\frac { 1 }{ 2 } \) litre
Therefore, each children will drink \(\frac { 1 }{ 2 } \) (half) litre milk
Question 8.
Nazeeb needs 2 \(\frac { 1 }{ 2 } \) meter (two and half) cloth to make a payjama. How much(RBSESolutions.com)cloth he needs to make three such payjamas.
Solution.
∵ Cloth needed to make 1 payjama = 2 \(\frac { 1 }{ 2 } \) (Two and half) meter
∴ Cloth needed to make 3 payjamas
= 2 \(\frac { 1 }{ 2 } \) + 2 \(\frac { 1 }{ 2 } \) + 2 \(\frac { 1 }{ 2 } \)
= 2 + \(\frac { 1 }{ 2 } \) + 2 + \(\frac { 1 }{ 2 } \) + 2 + \(\frac { 1 }{ 2 } \)
= 6 + \(\frac { 1 }{ 2 } \) + \(\frac { 1 }{ 2 } \) + \(\frac { 1 }{ 2 } \)
= 7 \(\frac { 1 }{ 2 } \) meter
Therefore,7 \(\frac { 1 }{ 2 } \) (seven and half meter) cloth needed to make 3 payjamas.
Question 9.
17kg. wheat divided equally among 4 families then how much kg wheat each family will get ?
Solution.
Each family will get = 17 ÷ 4 = \(\frac { 17 }{ 4 } \)
= 4 \(\frac { 1 }{ 4 } \) kg.
Therefore, each family will get 4 \(\frac { 1 }{ 4 } \) (four and one by four) kg wheat.
Question 10.
14 litre kerosene filled(RBSESolutions.com)equally in 4 stoves, then how much kerosene will be filled in each stove ?
Solution.
Kerosene filled in each stove = 14 ÷ 4 = \(\frac { 14 }{ 4 } \) litre
= \(\frac { 7 }{ 2 } \) = 3 \(\frac { 1 }{ 2 } \) litre
Therefore, 3 \(\frac { 1 }{ 2 } \) (Three and half) litre kerosene will be filled in each stove.
Question 11.
Hemlata studied for 2 hours. She has read \(\frac { 3 }{ 4 } \) (Three by four) hour. Now, how much time is it to read ?
Solution.
Time is it to read Hemlata = \(\frac { 2 }{ 1 } \) – \(\frac { 3 }{ 4 } \)
\(\frac { 2\times 4 }{ 1\times 4 } -\frac { 3 }{ 4 } \)
\(\frac { 8 }{ 4 } \) – \(\frac { 3 }{ 4 } \) = \(\frac { 8-3 }{ 4 } \) = \(\frac { 5 }{ 4 } \) hours
= 1 \(\frac { 1 }{ 4 } \) hours
Therefore, 1 \(\frac { 1 }{ 4 } \) (one and one by four) hour is it to read Hemlata
Question 12.
Meena took \(\frac { 1 }{ 2 } \) litre milk, her sister took 1 \(\frac { 1 }{ 2 } \) liters of milk and brought it ?
How much milk came in the house ? If milk is ₹ 20 per litre then how much rupees did Meena spend and how much her sister did spend ?
Solution.
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