RBSE Solutions for Class 6 Maths Chapter 1 Know the Numbers In Text Exercise is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers In Text Exercise.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 6 |
| Subject | Maths |
| Chapter | Chapter 1 |
| Chapter Name | Know the Numbers |
| Exercise | In Text Exercise |
| Number of Questions | 34 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers In Text Exercise
Pg. No. 4
Question 1.
In the following group of numbers; Circle 
the greatest number and put (RBSESolutions.com) a cross (x) on the smallest number.
(i) 4536, 4892, 4370, 4452
(ii) 15623, 15073,15189, 15800
(iii) 25286, 25245, 25270, 25210
(iv) 6895, 23787, 24569, 24659
(v) 4685, 4444, 3847, 9071
Solution.
The lartgest number in the numbers is the circle and the smallest group of numbers is cross (x) as follows :
Question 2.
Complete the (RBSESolutions.com) following table :
Draw on the greatest number and (
) on the smallest number given in above table.
Solution.
On completing the table :
Pg. No. 6
Question 1.
Write the number names for (RBSESolutions.com) the following digits.
(i) Five thousand five – 5,005
(ii) Five thousand four hundred thirty eight – …….
(iii) Thirty eight bousand four hundred – …….
(iv) Sixty five thousand seven hundred forty – …….
(v) Eighty nine thousand three hundred twenty four – …….
(vi) Twenty lakh five thousand two – …….
(vii) Eighty five Iakh eight hundred one – …….
(viii) Seven lakh seven thousand seven – …….
Solution.
Following are the number names –
(i) Fivs thousand five – 5,005
(ii) Five thousand four hundred thirty eight – 5,438
(iii) Thirty eight thousand four hundred – 38,400
(iv) Sixty five thousand seven hundred forty – 65,740
(v) Eighty nine thousand three hundred twenty four – 89,324
(vi) Twenty lakh five thousand two – 20,05,002
(vii) Eighty five Iakh eight hundred one – 85,00,801
(viii) Seven Iakh seven thousand seven – 7,07,007
Question 2.
Keeping the place value of uumber six at the same place and (RBSESolutions.com) jumbling the digits of number 6350947; the smallest number shall be:
(i) 6975430
(ii) 6043579
(iii) 6034579
(iv) 6034759
Solution.
Required number will be 6034579. Thus, option (iii) is correct.
Question 3.
The largest five digit number using digits 7, 8 and 9 is :
(i) 98978
(ii) 99897
(iii) 99987
(iv) 98799
Solution.
Required number will be 99987. Thus, option (iii) is correct.
Question 4.
Complete the (RBSESolutions.com) following table :
Discuss with your friends and write the numbers in descending order.
Solution.
Completing the table
Writting the numbers in descending order –
99,99,999 > 98,76,543 > 57,68,423 > 40,50,607 > 32,05,004 > 10,00,000
Pg. No. 7
Question 1.
Complete the (RBSESolutions.com) following table –
Write the numbers given in the table in ascending and descending order.
Solution.
Completing the table.
Writing the numbers in ascending order –
1,00,00,000 < 4,35,01,076 < 4,53,10,670 < 6,50,41,300 < 7,65,43,201 < 9,09,09,009
Writing the numbers in descending order –
9,09,09,009 > 7,65,43,201 > 6,50,41,300 > 4,53,10,670 > 4,35,01,076 > 1,00,00,000
Pg. No. 15
Question 1.
Take various kinds of things in your hand (wheat, corn, soyabean, pebbles etc.) and ask your (RBSESolutions.com) friend to estimate the number. Now count it.
Solution.
Question 2.
Divide into groups of 4 in your class and estimate their weights and fill it in the following :
Now weight the children on weighing machines and find out –
1. How many of your guessed the correct weight ?
2. How many of you guessed the weight close to the actual weight ?
3. How many of you guessed the (RBSESolutions.com) weight not close to the actual weight ?
Solution.
Prepare group of 4-4 students of class and their estimated and actual weights are like this –
1. Following children gives correct weight – Vikas, Rahul, Neel, Roli, Sonal, Babita and Seema.
2. 6 students estimate nearest to actual weight.
3. 3 students estimate far to actual weight.
Question 3.
Discuss with your friends (RBSESolutions.com) and guess following :
1. Estimated distance of the school from your house is …………….. m/km.
2. Esimated length of classroom is …………….. feet, width is feet.
3. Estimated number of books in the library is ……………..
Solution.
After discuss with friends and estimating obtained distances are –
1. 5,
2. 8, 10
3. 3000
Pg. No. 1-2
Question 1.
Think about the situations, where we use numbers.
Solution.
We use numbers daily as-counting of students chairs, tables, door windows, fans, etc.
Question 2.
Ramesh and Afsana formed a four digit number (RBSESolutions.com) using digit 3, 5, 7, 8. Using these numbers, you also form different numbers. Ask your friend to arrange them in ascending and descending order.
Solution.
= 3578, 3758, 3785, 3587, 3857, 3875, 5378, 5387, 5837, 5873, 5738,5783,7358, 7385, 7538, 7583, 7835, 7853, 8357, 8375,8735,8753, 8537, 8573
Numbers in ascending order are as follows :
3578, 3587, 3758, 3785, 3857, 3875, 5378,5387, 5738, 5783, 5837, 5873, 7358, 7385,7538,7583, 7835, 7853, 8357, 8375, 8537, 8573, 8735, 8753
Numbers in descending order are as follows :
8753, 8735, 8573, 8537, 8375, 8357, 7853, 7835, 7583, 7538, 7385, 7358, 5873, 5837, 5783, 5738, 5387, 5378, 3375, 3857, 3785, 3758, 3587, 3578
Question 3.
Which is the smallest number among the numbers you made ?
Solution.
3578 is the smallest number.
Question 4.
Form a five digit number using 4, 5, 2, 6 and 3. You also form (RBSESolutions.com) more numbers of 5-digit using these digits and write in following table.
Solution.
Using digits 4, 5, 2, 6 and 3, 5-digit number are formed in the following table –
Question 5.
Among the numbers 64532 and 64352 which (RBSESolutions.com) is greater? How?
Solution.
Compare the numbers as follows –
Thus, number 64532 is greater than 64352.
Pg. No. 3
Question 1.
Can I compare these numbers even without place value of each?
Solution.
Yes, in the following way :
Ten thousand’s and thousand place value digits are same in both of the above numbers. 5 is at the hundreth places in 64532 and 3 is at the hundreth place in 64352. Therefore, 64532 is greater.
Question 2.
Compare the numbers 56432 and 56342 from (RBSESolutions.com) left to right and see which is the bigger number.
Solution.
On comparing numbers –
∴ Number 56432 is greater than 56342.
Pg. No. 5
Question 1.
Take six digits of your choice and form different numbers and compare them.
Solution.
Taking 6 digits, 7, 4, 8, 3, 5, 9 and forming the number –
345789,754398,987543,839547,495378,589374 On comparing –
987543 > 839547 > 754398 > 589374 > 495378 > 345789
Question 2.
Complete the following table –
Solution.
On completing table :
Question 3.
Write the given numbers is table, in (RBSESolutions.com) ascending order.
Solution.
Writting the numbers in ascending order :
1,0, 000 < 2,43,596 < 3,52,027 < 4,72,280 < 5,67,890 < 6,04,307 < 7,00,295 < 9,99,999
Question 4.
What number will we get when we add 1 to the largest number of six digit?
Solution.
We know that largest 6-digit number is 9,99,999.
So we add 1 to 9,99,999 and we get 9,99,999 + 1 = 10,00,000
Question 5.
How do you read 10,00,000?
Solution.
We read this number as ten lakh.
Question 6.
How we read (RBSESolutions.com) number 15,40,400?
Solution.
15,40,400 will be read as : Fifteen lakh forty thousand four hundred.
Think
Pg. No. 9
Question 1.
How many lakhs is equal to one million?
Solution.
Ten lakhs.
Question 2.
How many millions is equal to one crore
Solution.
10 million.
Question 3.
Write five large numbers in Indian (RBSESolutions.com) and International system.
Solution.
Five largo numbers in Indian and International system are as follows :
Pg. No. 12-13
Question 1.
Detail of one month’s purchase from Khichdi Kirana Store is as follows :
(1) Can you find out the total weight of things sold by khichdi kirana store lat month? (excluding the weight of soapcake).
(2) What is the total weight of soap cake in kilogram sold last month?
(3) How many amount of money did Kirana Store get by selling sugar and tea?
(4) How much amount did Kirana store get by selling salt and chilli?
Solution.
(1) Total weight of things sold by Khichdi Kirana store is as follows –
(3) Money get from selling suger and tea is :
(4) Amount obtained from selling salt and chilli is :
Pg. No. 15
Question 1.
Tell, where you can estimate (RBSESolutions.com) the distance?
Solution.
Generally, student estimate distance between house and school, from house or school to tuition centre, from house to playground etc.
Pg. No. 16
Question 1.
Think about the situation where we work with the rounded off number and when we need the exact number.
Solution.
In distance, speed, time etc., we can estimate the number. But in rent, bill, salary etc. we need exact number.
Question 2.
Rounding numbers to the nearest tens.
(i) Which flag is closer to 10 ?
(ii) Which flag is closer to 20 ?
Solution.
(i) flag 13 is closer to 10.
(ii) Flag 17 is closer to 20.
Question 3.
How do we round off the numbers (RBSESolutions.com) written on the number line ?
Solution.
Rounding off the number on number line –
(i) Unit digit in number 54 = 4 < 5
Thus, tens digit in number 54 = 50
Unit digit in 66 = 6 > 5
Thus, tens digit = 6 + 1 = 7
Thus, approximate value
of tens is 66 = 70
(ii) Unit digit in number 278 = 8 > 5
Tens digit = 7 + 1 = 8
Thus, approximate value of
tens in 278 = 280
Unit digit in number 283 = 3 < 5
Thus, approximate value of
tens in 283 = 280
Question 4.
Are 278 and 283 both (RBSESolutions.com) rounded off to 280? Why?
Solution.
Yes, rounded off number 278 and 283 will be 280, rounded off 78 in 278 is 80 and rounded off 83 in 283 is 80 also.
Question 5.
Learn these (Pg. No. 17)
9 + 1 = 10
99 + 1 = 100
999 + 1 = ……………..
9,999 + 1 = ……………..
99,999 + 1 = ……………..
9,99,999 + 1 = ……………..
99,99,999 + 1 = 1,00,00,000
10 × 10 = 100
100 × 10 = 1,000
1,000 × 10 = 10,000
10,000 × 10 = 1,00,000
1,00,000 × 10 = 10,00,000
10,00,000 × 10 = 1,00,00,000
Solution.
9 + 1 = 10
99 + 1 = 100
999 + 1 = 1,000
9,999 + 1 10,000
99,999 + 1 = 1,00,000
9,99,999 + 1 = 10,00,000
99,99,999 + 1 = 1,00,00,000
Pg. No. 18
Question 1.
Identify the. (RBSESolutions.com) pattern
0 × 9 + 1 = 1
1 × 9 + 2 = 11
12 × 9 + 3 = 111
123 × 9 + 4 = 1111
1234 × 9 + 5 = ………
…………………………………
…………………………………
9 × 9 + 7 = 88
98 + 9 + 6 = 888
987 × 9 + 5 — 8888
9876 × 9 + 4 = 88888
98765 × 9 + …. = ………
Solution.
Pattern is as follows –
0 × 9 + 1 = 1
1 × 9 + 2 = 11
12 × 9 + 3 = 111
123 × 9 + 4 = 1111
1234 × 9 + 5 = 11111
12345 × 9 + 6 = 111111
123456 × 9 + 7 1111111
9 × 9 + 7 = 88
98 × 9 + 6 = 888
987 × 9 + 5 = 8888
9876 × 9 + 4 = 88888
98765 × 9 + 3 = 888888
987654 × 9 + 2 = 8888888
9876543 × 9 + 1 = 88888888
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