RBSE Solutions for Class 6 Maths Chapter 15 Data Handling Ex 15.1

RBSE Solutions for Class 6 Maths Chapter 15 Data Handling Ex 15.1 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 15 Data Handling Exercise 15.1.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 6
Subject Maths
Chapter Chapter 15
Chapter Name Data Handling
Exercise Ex 15.1
Number of Questions 6
Category RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 15 Data Handling Ex 15.1

Question 1.
Identify the primary and secondary data (RBSESolutions.com) from the following
(i) Numbers of students present from each class during morning prayer on a particular day.
(ii) Numbers of students from each caste gathered from the student’s attendance
(iii) Number of vehicles passing through a road between 9 a.m. to 11 a.m. on a particular day.
(iv) Listing the distances of Jaipur from major towns of Rajasthan after looking at map.
Solution:
(i) Primary data
(ii) Secondary data
(iii) Primary data
(iv) Secondary data

RBSE Solutions

Question 2.
Following is the data about the ages of 30 students (RBSESolutions.com) of class VI. Prepare a table using tally marks.
11, 12, 11, 13, 14, 11, 12, 13, 15, 13, 13, 16, 14, 13, 14, 13, 12, 14, 13, 12, 14, 13, 13, 12, 14, 14, 13, 12, 13, 14
(i) How many students have completed 13 years of age?
(ii) Maximum number of students are of which age?
(iii) How many students have not yet completed 14 years of age?
Solution:
Tally marks table :
RBSE Solutions for Class 6 Maths Chapter 15 Data Handling Ex 15.1 image 1
(i) 11 + 8 + 1 + 1 = 21 students completed 13 years of age.
(ii) Maximum number (11) students are of 13 years age.
(iii) 3 + 6 + 11 = 20 students have not yet completed 14 years of age.

Question 3.
25 students participated in an Essay (RBSESolutions.com) competition on the topic “Clean India-Healthy India”. Following is the data about their marks obtained out of maximum marks 10.
6, 7, 7, 5, 8, 9, 8, 6, 7, 5, 8, 6, 6, 5, 4, 7, 6, 8, 8, 9, 7, 5, 9, 8, 10
Prepare a table using tally marks and answer the following questions
(i) Number of students who obtained less than or equal to 6 marks.
(ii) Number of students who obtained more than 6 marks.
(iii) Number of students who obtained 8 marks.
Solution:
Tally marks table :
RBSE Solutions for Class 6 Maths Chapter 15 Data Handling Ex 15.1 image 2
(i) Number of students obtained less than or equal to 6 marks = 5 + 4 + 1 = 10
(ii) Number of students obtained more than 6 marks = 5 + 6 + 3 + 1 = 15
(iii) Number of students who obtained 8 marks = 6

Question 4.
Number of members in five families are (RBSESolutions.com) depicted by the following pictograph
RBSE Solutions for Class 6 Maths Chapter 15 Data Handling Ex 15.1 image 3
Observe the pictograph and answer (RBSESolutions.com) the following questions :
(i) Which family has maximum members?
(ii) Which family has minimum members?
(iii) What is the difference between number of family members of families D and C?
(iv) How many total number of members in all five families?
Solution:
(i) Family D has maximum members.
(ii) Family C has minimum members.
(iii) The difference between number of family members of families D and C = 6 – 2 = 4
(iv) Total members in all five families = 5 + 4 + 2 + 6 + 4 = 21

Question 5.
The pictograph below shows how many (RBSESolutions.com) envelops were sold by a post office during a week. Use the pictograph to answer the following questions
RBSE Solutions for Class 6 Maths Chapter 15 Data Handling Ex 15.1 image 4
(i) How many envelops (RBSESolutions.com) were sold on Wednesday?
(ii) On which day, maximum number of envelops were sold?
(iii) If cost of one envelop is 5, find the revenue generated by selling envelops on Monday.
(iv) How many envelops were sold during the week ? Find the revenue generated by selling envelops during the week.
Solution:
(i) 5 x 5 = 25 envelops were sold on Wednesday
(ii) On Monday, maximum number of envelops were sold.
(iii) If cost of one envelop is 5, then cost of envelops sold on Monday = 7 × 5 × 5 = ₹ 175
(iv) (7 + 4 + 5 + 6 + 3 + 2) = 27 × 5 = 135 envelops were sold during the week and their cost = 135 × 5 = ₹ 675

RBSE Solutions

Question 6.
The following pictograph shows the (RBSESolutions.com) number of students who like to play different sports in a class of 30 students
RBSE Solutions for Class 6 Maths Chapter 15 Data Handling Ex 15.1 image 5
(i) How many students play kho – kho?
(ii) Which sport is played by maximum number of students?
(iii) How many students play none of the sports?
Solution:
(i) 8 students (RBSESolutions.com) play kho – kho.
(ii) Cricket is played by maximum number of students.
(ii) Students who play none of the sports
= 30 – (6 + 8 + 5 + 11) = 30 – 30 = 0
Thus, each students play any one of the given sports.

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