RBSE Solutions for Class 7 Maths Chapter 14 सरल समीकरण In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 14 सरल समीकरण In Text Exercise.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 7 |
| Subject | Maths |
| Chapter | Chapter 14 |
| Chapter Name | सरल समीकरण |
| Exercise | In Text Exercise |
| Number of Questions | 2 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 7 Maths Chapter 14 सरल समीकरण In Text Exercise
करो और सीखो
(पृष्ठ 155)
प्रश्न 1
रिक्त स्थानों की पूर्ति कीजिए।
तुला विधि
7x + 6 = 34
7x + 6 – …… = 34 – …….
7x = …..
x = …….
पक्षांतरण विधि
7x + 6 = 34
7x = 34 -….
x = \(\frac { ……… }{ 7 }\)
x = 4
उत्तर की जाँच
LHS = 7x +6
= 7 x ….. + 6
= …… + 6 = RHS
हल:
तुला विधि
7x + 6 = 34
7x + 6 – 6 = 34 – 6
7x = 28
x = 4
पक्षांतरण विधि
7x + 6 = 34
7x = 34 – 6
x = \(\frac { 28 }{ 7 }\)
x = 4
उत्तर की जाँच
LHS = 7x + 6
= 7 x 4 + 6
= 28 + 6 = 34 = RHS
प्रश्न 2
सही/गलत बताइए।
(i) 4x +x – 13 = 7 में x = 4 सही/गलत
(ii) 3x – 8 = 25 में x = 12 सही/गलत
(iii) 7x – 5 = 3x +7 में x=3 सी/गलत
(iv) 5x – 7 = 4+1 में r = 5 सही/गलत
हल:
(i) 4x + x – 13 = 7 में x = 4 रखने पर
L.H.S. = 4x + x – 13 = 5x – 13
= 5 x 4 – 13
= 20 – 13 = 7 = RHS
अत: 4x + x -13 = 7 में x = 4 सही है।
(ii) 3x – 8 = 25 में x = 12
LHS = 3 – 8
= 3 x 12 – 8
= 36 – 8 = 28 ≠ RHS
अतः 3x – 8 = 25 में x = 12 गलत है।
(iii) 7x – 5 = 3x +7 में x = 3 रखने पर
7x – 5 = 3x +7
7 x 3 – 5 = 3 x 3 + 7
21 – 5 = 9 + 7
16 = 16
LHS = RHS
अत: 7x – 5 = 3x +7 में x = 3 सही है।
(iv) 5x – 7 = 4x +1 में x = 5
LHS व RHS में x= 5 रखने पर
5 x 5 – 7 = 4 x 5 + 1
25 – 7 = 20 + 1
18 ≠ 21
LHS ≠ RHS
अत: 5x – 7 = 4x + 1 में x = 5 गलत है।
We hope the RBSE Solutions for Class 7 Maths Chapter 14 सरल समीकरण In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 14 सरल समीकरण In Text Exercise, drop a comment below and we will get back to you at the earliest.