RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1

RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.1.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Maths
Chapter Chapter 2
Chapter Name Fractions and Decimal Numbers
Exercise Ex 2.1
Number of Questions 7
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1

Question 1
Find 5 equivalent fractions (RBSESolutions.com) of each fraction given below
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q1
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q1a
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q1b
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q1c

RBSE Solutions

Question 2
Use >, < and = sign for (RBSESolutions.com) comparison of the following:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q2
Solution:
(i) L.C.M of 5 and 7 = 5 x 7 = 35
∴ Denominators of each fraction should be 35.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q2a

(ii) L.C.M of 8 and 16 = 16
∴ Denominator of (RBSESolutions.com) equivalent fraction should be 16.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q2b

(iii) L.C.M of 15 and 17 = 15 x 17 = 255
∴ Denominators of each fraction should be 225.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q2c

(iv) RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q2d
L.C.M of denominators 3 and 8 = 3 x 8 =24
∴ Denominators of (RBSESolutions.com) Equivalent fraction be 24.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q2e

Question 3
Arrange the (RBSESolutions.com) following in ascending order:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q3
Solution:
(i) L.C.M of denominator 5, 7 and 10 = 5 x 2 x 7 = 70
∴ Denominator of Equivalent fractions should be 70.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q3a

(ii) L.C.M of 9, 3, 21 is = 3 x 3 x 7 = 63
∴ Denominator (RBSESolutions.com) of Equivalent fractions should be 63.
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q3b
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q3c

RBSE Solutions

Question 4
Solve:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q4
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q4a
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q4b

Question 5
A rectangular photo (RBSESolutions.com) whose length 2\(\frac { 3 }{ 4 }\) inch and breadth \(\frac { 7 }{ 6 }\)inch. Find its perimeter.
Solution:
Length of rectangular photo = 2\(\frac { 3 }{ 4 }\) = \(\frac { 11 }{ 4 }\) inch
and breadth of rectangular photo = 2\(\frac { 7 }{ 6 }\) inch
∴ P = 2(l + b)
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q5
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q5a
∴ Perimeter of rectangular photo = \(\frac { 47 }{ 6 }\) = 7 \(\frac { 5 }{ 6 }\) inch.

RBSE Solutions

Question 6
Sheela took 3 \(\frac { 3 }{ 5 }\) hours in whitewashing (RBSESolutions.com) a shop and Necia completed whitewashing of similar shop in 3 \(\frac { 5 }{ 7 }\) hours. Who took more time and how much?
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q6

Question 7
Distributing the brithday cake (RBSESolutions.com) among Reena, Teena and Meena; \(\frac { 2 }{ 5 }\) part and Teena given \(\frac { 1 }{ 3 }\) part and remaining part was given to Meena. Find the Meena’s shate.
Solution:
Part of Reena = \(\frac { 2 }{ 5 }\) and part of Teena = \(\frac { 1 }{ 3 }\)
Total part of Reena and Teena = \(\frac { 2 }{ 5 }\) + \(\frac { 1 }{ 3 }\)
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.1 Q7

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