RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3

RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.3.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Maths
Chapter Chapter 2
Chapter Name Fractions and Decimal Numbers
Exercise Ex 2.3
Number of Questions 6
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3

Question 1
Find:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q1
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q1a
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3

RBSE Solutions

Question 2
Find the reciprocal (RBSESolutions.com) of the following:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q2
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q2a

Question 3
Find :
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q3
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q3a

Question 4
Find :
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q4
Solution:
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q4a
RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 Q4b

Question 5
What will be number of \(\frac { 1 }{ 4 }\) parts of bread if each of 6 breads is (RBSESolutions.com) divided into equal parts of \(\frac { 1 }{ 4 }\)?
Solution:
Total breads = 6, each bread is to be divided in \(\frac { 1 }{ 4 }\)th part
∴ Nurnber of \(\frac { 1 }{ 4 }\) parts = 6 ÷ \(\frac { 1 }{ 4 }\) = 24 parts.

Question 6
How many \(\frac { 1 }{ 2 }\)cm log (RBSESolutions.com) pieces can be cut of 11 \(\frac { 1 }{ 2 }\) long ribon?
Solution:
Length of ribon = 11\(\frac { 1 }{ 2 }\) cm = \(\frac { 23 }{ 2 }\) cm
∴ Number of pieces to be cut = \(\frac { 23 }{ 2 }\) ÷ \(\frac { 1 }{ 2 }\)
=\(\frac { 23 }{ 2 }\) x \(\frac { 2 }{ 1 }\) = \(\frac { 23\times 1 }{ 1\times 1 }\) pieces

RBSE Solutions

We hope the RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.3, drop a comment below and we will get back to you at the earliest.