RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions

RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 8
Subject Maths
Chapter Chapter 13
Chapter Name Comparison of Quantities
Exercise Additional Questions
Number of Questions 32
Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions

I. Objective Type Questions

Question 1.
The basic salary of a person is Rs 1,40,000. If his salary is increased by 10%, than his new salary will be
(a) Rs 1,50,000
(b) Rs 1,40,010
(c) Rs 1,54,000
(d) Rs 1,40,100

Question 2.
Yasha mark up the(RBSESolutions.com)computers I am selling by 20% and sell then at a discount of 15%. What is my net gain percent?
(a) 1%
(b) 2%
(c) 3%
(d) 4%

Question 3.
The printed price of a jeans is Rs 220. The discount 20% is given on this. Selling price is
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-1

Question 4.
There are 15 apples and 5 oranges in a bucket. Then what is the ratio of number of oranges to number is apples
(a) 1:3
(b) 15 : 5
(c) 3 : 1
(d) 5 : 20

RBSE Solutions

Question 5.
The compound(RBSESolutions.com)interest of ? 20,000 at the rate of 8% per year for 2 years is
(a) Rs 3,200
(b) Rs 1,728
(c) Rs 1,600
(d) Rs 3,328

Question 6.
If the cost of one kg sugar is Rs 18, then cost of 3 kg sugar is Rs 54. Thus relation is called
(a) Direct Proportion
(b) Inverse Proportion
(c) Ratio
(d) None of the above

Question 7.
If number of purchased items is increased, then their cost will be
(a) decreased
(b) increased
(c) decreased or increased
(d) neither(RBSESolutions.com)increased nor decreased

RBSE Solutions

Question 8.
If two variables are related to each other in such a way, that if we increase the value of first variable then the value of second variable decreases, and converse is also occurred. Thus related is called
(a) ratio
(b) inverse proportional
(c) direct proportional
(d) None of these

Question 9.
If interest is calculated quarterly then time period is
(a) double
(b) four times
(c) triple
(d) No change

RBSE Solutions

Question 10.
80% students are good at maths out of 25 students. How many(RBSESolutions.com)students are not good at maths?
(a) 10
(b) 5
(c) 15
(d) 20

Answers
1. (c)
2. (b)
3. (c)
4. (a)
5. (d)
6. (a)
7. (b)
8. (b)
9. (b)
10. (b)

RBSE Solutions

II. Fill in the blanks

Question 1.
The concession on printed rate is called___

Question 2.
Sale tax is added to cost price of item is called___

Question 3.
The interest(RBSESolutions.com)compounded on total amount of previous year (A = P + I) is called___

Question 4.
The direct ratios is x and y then \(\frac { { x }_{ 1 } }{ { y }_{ 1 } } =\)____

RBSE Solutions

Question 5.
If the speed of a vehicle is increased then the time taken for travelling same distance is___

Answers
1. discount
2. VAT
3. Compound Interest
4. \(\frac { { x }_{ 2 } }{ { y }_{ 2 } }\)
5. decreased.

III. True/False Type Questions

Question 1.
When interest is(RBSESolutions.com)added yearly, the compound interest \(P\left[ { \left( 1+\frac { R }{ 100 } \right) }^{ n }-1 \right] \)
Where P = Principal; R = Rate; n = Time

Question 2.
When interest is added on half yearly, then rate of interest reduces to half.

RBSE Solutions

Question 3.
The percentage form of 1 : 4 is 25%.

Question 4.
The interest is(RBSESolutions.com)based on the amount deposited in bank.

Question 5.
There is a direct relation between height of a tree and number of leaves on its branches.

Answers
1. True
2. True
3. True
4. True
5. False.

RBSE Solutions

IV. Matching Type Questions

Part 1 Part 2
1. Formula of calculating simple interest (a) Cost price + Profit
2. Selling price (if profit exist) (b) Constant
3. If x and y are in inverse relationship, then xy = (c) 1 : 10
4. Ratio between 50 paise to Rs 5 (d) \(\frac { PRT }{ 100 }\)

Answers
1. ↔ (d),
2. ↔ (a),
3. ↔ (b),
4. ↔ (c)

RBSE Solutions

V. Very Short Answer Type Questions

Question 1.
The meaning of twice of a number is to increase 100%. What is the percentage decrease if number reduces to its half?
Solution
Percentage loss
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-2
= 50%

Question 2.
If any amount is borrowed for one year at the 16% rate of interest p.a. If interest is compounded for quarterly, then how many times will the interest be paid?
Solution
1 year = 4 quarters
∴ Interest will be(RBSESolutions.com)paid 4 times in a year.

RBSE Solutions

Question 3.
After selling a plot for Rs 61,200, the gain is 2%. What is the cost price of plot?
Solution
Let plot cost price Rs x
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-3
Hence, the required(RBSESolutions.com)cost price of plot is Rs 60,000.

Question 4.
The cost price of a scooter is Rs 42,000. If it depreciates at a rate of 8%, what will be the price of scooter after 1 year?
Solution
Price of scooter after 1 year
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-4
= Rs 38,640.

RBSE Solutions

Question 5.
In a government school 25% Neem plants were shown during(RBSESolutions.com)environment pakwara (fortnight). If there are 180 plants in total then how many Neem plants are there?
Solution
Total plants = 180
Percentage of Neem plants = 25%
Hence the required number of Neem plants = 25% of 180
= \(\frac { 25 }{ 100 }\) × 180
= 45

Question 6.
Convert 2 : 5 ratios into percentage.
Solution
= 2 : 5
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-5
= 40%

RBSE Solutions

VI. Short Answer Type Questions

Question 1.
Simple interest for 5 years on some money is \(\frac { 2 }{ 5 }\) of total amount (A). Find the rate of simple interest
Solution
Amount = Principal + Simple Interest
Principal x Time x Rate 100
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-6
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-7
⇒ 5 PR = 40 P + 2 PR
⇒ 5R = 40 + 2R
⇒ 5R – 2R = 40
⇒ 3R = 40
⇒ R= \(\frac { 40 }{ 3 }\) = \(13\frac { 1 }{ 3 }\)
Hence, the required rate(RBSESolutions.com)of simple interest is \(13\frac { 1 }{ 3 }\) %

RBSE Solutions

Question 2.
The population of a town before 3 years was 25,000. If grows at 10%, 15% and 8% in consecutive three years. Find the present population.
Solution
Present Population
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-8
= 34,155

RBSE Solutions

Question 3.
Find the rate of which a sum of money will \(\frac { 81 }{ 16 }\) times itself in one year, if the interest is compounded quarterly.
Solution
Let R% yearly be the rate of interest.
Then quarterly(RBSESolutions.com)rate of interest = \(\frac { R }{ 4 }\) %
1 year = 4 quarters
According to question,
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-9
Hence, the required rate of interest is 200% p.a.

RBSE Solutions

Question 4.
A farmer took loan of Rs 20,000 from Nationalized Bank for his agricultural work. If bank charges interest on the rate of 14% yearly and the interest is compounded yearly. What is the total amount to be paid after 2 years and 6 months?
Solution
Loan amount = Rs 20,000
Rate of(RBSESolutions.com)interest = 14% yearly
Time = 2 years 6 months
= 2 years + \(\frac { 6 }{ 12 }\) year
= \(\frac { 5 }{ 2 }\) years
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-10
Total Amount = Principal Amount + Interest
= 20,000 + 7,000
= Rs 27,000
Hence the total amount to be paid is Rs 27,000.

RBSE Solutions

Question 5.
A farmer has enough food for 20 animals for 6 days. If he increases 10 more animals then for how many days this food will be enough?
Solution:
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-11
Let required days be x.
Here inverse relation occurred.
30 : 20 :: 6 : x
Product of outer(RBSESolutions.com)terms = Product of middle terms
⇒ 30 × x = 20 × 6
⇒ \(x=\frac { 20\times 6 }{ 30 } =4\)
Hence, the required days are 4.

RBSE Solutions

Question 6.
Suppose in 2 Kg. sugar, there are 9 x 106 crystals. How many crystals will be there in 1.2 kg. sugar?
Solution
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-12
Let x crystals be in 1.2 kg sugar.
Then, 2 : 1.2 :: 9 × 106 : x
Product of outer terms = Product of middle terms
⇒ 2 × x = 1.2 × 9 × 106
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-13
Hence, the required crystals are 5.4 x 106.

RBSE Solutions

Question 7.
In class VIII 60% students in Maths obtained grade A out of 45 students. How many students got A grade in Maths?
Solution
Total number of students = 45 %
of students getting grade A in Maths = 60%
Number of(RBSESolutions.com)students getting grade A in Maths
= 60% of 45 = \(\frac { 60 }{ 100 }\) × 45 = 27
∴ Number of students getting grade A in Maths = 27

Question 8.
A businessman sold two television sets at the rate of Rs 36,000 for each television set If he gets 20% profit on one television set and 20% loss on the other television set then find the percentage of profit or loss in total transaction?
Solution
Selling price of one television = Rs 36,000
Let cost(RBSESolutions.com)price be Rs x
Percentage profit = 20%
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-14
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-15

RBSE Solutions

Question 9.
Naval borrowed Rs 84,000 from a nationalized bank for \(1\frac { 1 }{ 2 }\) years at the rate of 10% per annum. Compute the total compound interest(RBSESolutions.com)payable by Naval after \(1\frac { 1 }{ 2 }\) year, if the interest is compound half yearly.
Solution
\(1\frac { 1 }{ 2 }\) years = 3 half years
Principal Amount = Rs 84,000
Rate = 10%
= 5% half yearly
Total amount = principal amount
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-16
∴ Compound Interest = Total Amount – Principal Amount
= 97,240.50 – 84,000
= Rs 13,240.50

RBSE Solutions

Question 10.
Rahul sold a scooter for Rs 18,750 at a loss of 25%. Find the cost price of the scooter.
Solution
Let the required(RBSESolutions.com)cost price of scooter be Rs x.
Loss = 25% of x
Selling Price = Rs 18,750
Therefore,
Cost Price – Loss = Selling Price
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-17
= 25,000
Hence the required cost price of scooter is Rs 25,000..

RBSE Solutions

Question 11.
Find compound interest of Rs 24,000 for \(1\frac { 1 }{ 2 }\) years at the rate of 8% per year, when interest is calculated yearly.
Solution
Time = \(1\frac { 1 }{ 2 }\) year
Principal(RBSESolutions.com)Amount = Rs 24,000
Annual interest rate = 8%
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-18
∴Amount = Rs 26,956.80
Compound Interest = Amount – Principal
= 26,956.80 – 24,000
= Rs 2,956.80

RBSE Solutions

Question 12.
The population of a town increases at annual rate of 8%. If present population of town is 17,496 then find population of town before 2 years. Solution
Present Population = 17,496
Time = 2 years
Rate of increase = 8%
Let the(RBSESolutions.com)population of town before 2 years be x.
Hence, Present Population
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-19
⇒ x = 15,000
Hence the required population of town before 2 years = 15,000

RBSE Solutions

Question 13.
Payal took loan of Rs 20,000 for parlor from a nationalized(RBSESolutions.com)Bank. How much amount will she repay after 3 years, if annual rate of interest is 14% and interest is compounded annually?
Solution
Amount borrowed from Bank (P) = Rs 20,000
Time (n) = 3 years
Rate of interest = 14%
Condition = Interest is compounded annually
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions img-20
∴ Payal has to return Rs 29,631 to the bank.

RBSE Solutions

Question 14.
A businessman purchased goods for Rs 14,000. He paid Rs 50 for freight(RBSESolutions.com)and Rs 150 for wages. To earn 5% profit, at what price he should sell goods?
Solution
Cost price of goods = Rs 14,000
Auto rent = Rs 50
Wages = Rs 150
Total cost(RBSESolutions.com)price of goods
= Rs (14,000 + 50 + 150)
= Rs 14,200
Wants to earn profit = 5%
∴Profit = 5% of 14,200
= \(\frac { 14,200X5 }{ 100 }\)
= Rs 710
∴ Selling price of goods = Rs(14,200 + 710)
= Rs 14,910.

RBSE Solutions

We hope the given RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions, drop a comment below and we will get back to you at the earliest.