RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Exercise 13.2.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 8 |
| Subject | Maths |
| Chapter | Chapter 13 |
| Chapter Name | Comparison of Quantities |
| Exercise | Exercise 13.2 |
| Number of Questions | 9 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2
Question 1.
Mohan purchases some mattresses for Rs. 7250. After some time he sold them for Rs. 6090. Find out loss percentage.
Solution:
Cost price = Rs 7,250
Selling price = Rs 6,090
∴ Loss = Cost price – Selling price
= 7,250 – 6,090
= Rs 1,160
∵ Loss(RBSESolutions.com)on Rs 7,250 = 1,160
∴ Loss on Rs 1 = Rs \(\frac { 1160 }{ 7250 }\)
∴ Loss on Rs 100 = Rs \(\frac { 1160 }{ 7250 }\) x 100
= Rs 16
Hence, % loss of Mohan = 16%
Question 2.
Due to increase in salary of Ajit Singh by 12% new salary becomes Rs. 25760. Find his previous salary.
Solution:
Let Rs x be the previous salary.
Percentage increase = 12%
⇒ x = 23,000
Hence, the previous salary was Rs 23,000.
Question 3.
Manjeet mark up price on a pump by increasing 40%. If he wishes to sell it after providing subsidy of 40% then find out profit or loss percentage.
Solution:
Let Rs x be the cost price of pump set.
∴ Marked price = x + 40% of x
= 16%
Hence, loss percentage is 16%.
Question 4.
Cost of a moped is t 54,000. Now price increased by 14%, then tell the price to be paid for moped.
Solution:
Price of Moped = Rs 54,000
Percentage(RBSESolutions.com)increase in cost = 14%
Increase = 14% of 54,000
= 54000 x \(\frac { 14 }{ 100 }\)
= Rs 7650
∴ New cost of Moped = 54,000 + 7,560
= Rs 61,560
Hence, the required price of Moped is Rs 61,560.
Question 5.
A businessman purchased goods for Rs. 14000. He paid Rs. 350 as auto rent and Rs. 150 as wages. For earning 5% profit, at what price he should sell goods.
Solution:
Cost price of(RBSESolutions.com)products = Rs 14,000
Transportation = Rs 350
Labor = Rs 150
∴ Total cost price of products
= 14,000 + 350 + 150
= Rs 14,500
Profit % = 5%
∴ Profit = 5% of 14,500
= 14,500 x \(\frac { 5 }{ 100 }\)
= Rs 725
∴ Selling Price = Total Cost Price + Profit
= 14,500 + 725
= Rs 15,225
Hence, he will sell his products for Rs 15,225.
Question 6.
A furniture seller sold two dressing tables at the rate of Rs. 7200. Out of them 20% profit obtained on one table and 20% loss on another. How much profit or gain percentage is(RBSESolutions.com)obtained in whole transaction?
Solution
Selling Price of one dressing table = Rs 7,200
Let cost price = Rs x
gain % = 20%
∴Gain = 20% of x
Hence total loss % = 4%, for the two dressing tables.
Question 7.
Manoj paid Rs. 6500 as interest on loan of Rs. 52000 after two years. Find percentage interest paid by Manoj.
Solution
Interest of 2 years = Rs 6,500
= Rs 6.25
Hence, the required of interest is 6.25%.
Question 8.
In what time will principal of Rs. 3200 at rate of 8% become Rs. 3840?
Solution:
Principal(RBSESolutions.com)Amount = Rs 3,200
Amount = Rs 3,840
∴ Simple Interest = Amount – Principal
= 3,840 – 3,200
= Rs 640
= 2.5 years
= 2 years 6 month
Hence, Required Time = 2 years and 6 months.
Question 9.
Bhupendra took loan of Rs. 6300 at rate of 7% for 2 years and 8 months then tell what amount will be paid by him?
Solution
Principal = Rs 6,300
Time = 2 years & 8 months
= 2 years + 8 months
= 2 years + \(\frac { 8 }{ 12 }\) year
= 2 year + \(\frac { 2 }{ 3 }\) year
∴ Amount = Principal + Simple(RBSESolutions.com)Interest
= 6,300 + 1,176
= Rs 7,476
Hence, he will pay Rs 7,476.
We hope the given RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Exercise 13.2, drop a comment below and we will get back to you at the earliest.