RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2

RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 7 Construction of Quadrilaterals Exercise 7.2.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 8
Subject Maths
Chapter Chapter 7
Chapter Name Construction of Quadrilaterals
Exercise Exercise 7.2
Number of Questions 5
Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2

Question 1.
Construct a quadrilateral LIFT when LI = 4.0 cm., IF = 3.0 cm., TL = 2.5 cm., LF = 4.5 cm. and IT = 4.0 cm.
Solution
Draw a rough sketch of the given measurements:
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-1
Steps of Construction

  1. First of all we draw a line segment LI = 4.0 cm.
  2. Draw an arc of radius 2.5 cm. from point L and an arc of(RBSESolutions.com)radius 4 cm. from point I which cut at point T. Join TL and TI, so we obtained a triangle LIT.
  3. Draw an arc of radius 4.5 cm. from point L(RBSESolutions.com)and an arc of radius 3.0 cm. from point I which intersect each other at F. Join LF and IF.
  4. Join TF.
    Thus, we obtained a required quadrilateral LIFT.
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-2

RBSE Solutions

Question 2.
Construct a quadrilateral ABCD in which AB = 3.8 cm., BC = 3.0 cm., AD = 2.3 cm., AC = 4.5 cm. and BD = 3.8 cm. Measure the side CD.
Solution
first of all, we draw a rough sketch of the(RBSESolutions.com)quadrilateral of the given measurements:
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-3
Steps of Construction

  1. First of all, we draw a line segment AB = 3.8 cm.
  2. Draw an arc of radius 2.3 cm. from point A and an arc of radius 3.8 cm. from point B intersect each other at point D. Join AD and BD. So, we(RBSESolutions.com)obtained triangle ABD.
  3. Draw an arc of radius 4.5 from point A and an arc of radius 3 cm. from point B intersect each other at point C. Join AC and BC. Join CD.
    Thus, we obtained a quadrilateral ABCD.
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-4

RBSE Solutions

Question 3.
Construct a quadrilateral PQRS. In which PS = 6.0 cm., SR = 5.0 cm., RQ = 7.5 cm., PR = 6.0 cm. and SQ = 10.0 cm.
Solution
First of all, we(RBSESolutions.com)draw a rough sketch of the given measurements :
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-5
Steps of Construction

  1. First of all, we draw a line segment PQ = 7.5 cm.
  2. Draw an arc of radius 6 cm. from point P and an arc of radius 10 cm. from point Q intersecting each other at S. Join PS and QS. So, we(RBSESolutions.com)obtained triangle PQS.
  3. Draw, an arc of 6 cm. from point P and an arc of radius 7.5 cm. from point Q intersecting each other at R. Join PR, QR, and SR.
    Thus, we obtained the required quadrilateral PQRS:
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-6

RBSE Solutions

Question 4.
Construct a quadrilateral ABCD in which AB = BC = CD = 5.0 cm. and Diagonals AC = 6.7 cm. and BD = 5.9 cm.
Solution First of all we(RBSESolutions.com)draw a rough sketch of the given measurements :
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-7
Steps of Construction

  1. First of all we draw a line segment AB = 5 cm.
  2. Draw an arc(RBSESolutions.com)of radius 6.7 from point A and an arc of radius 5.0 cm. from B intersecting each other at point C. Join AC and BC. So, we obtained the triangle ABC.
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-8
  3. From point B, we draw an arc of radius 5.9 cm. and from point C draw an arc of radius 5 cm. intersecting each other at point
    D. Join BD and CD. Join AD. Thus, we obtained required quadrilateral ABCD.

RBSE Solutions

Question 5.
Construct a quadrilateral GOLD in which GO = 3.0 cm., OL = 2.5 cm., GD = 5.0 cm., GL = 4 cm. and OD = 7 cm.
Solution
Draw a rough sketch of the given measurements :
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-9
Steps of Construction

  1. First of all, we draw a line segment GO = 3.0 cm.
  2. From point G, we draw an arc of radius 4 cm. radius and from point O, we draw an arc of 2.5 cm. intersecting each other at L. Join GL and OL. So, we obtained triangle GOL.
  3. Again from(RBSESolutions.com)point G, draw an arc of 5 cm. and from a point, O draw an arc of 7 cm. intersecting each other at D. Joint GD and OD. Join DL.
    Thus, we obtained the required quadrilateral GOLD
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 img-10

We hope the given RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 7 Construction of Quadrilaterals Exercise 7.2, drop a comment below and we will get back to you at the earliest.