RBSE Solutions for Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1

RBSE Solutions for Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 9 Algebraic Expressions Exercise 9.1.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 8
Subject Maths
Chapter Chapter 9
Chapter Name Algebraic Expressions
Exercise Exercise 9.1
Number of Questions 4
Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1

Question 1.
Find the product of the following pairs of monomials.
(i) 3 × 5x
(ii) – 5p, – 2q
(iii) 7l², – 3n²
(iv) 6m, 3n
(v) – 5x², – 2x
Solution
(i) 3 × 5x
= 3 × 5 × x
= 15x
(ii) – 5p,- 2q
= (- 5) × p × (- 2) × q
= (- 5) × (- 2) × p × q
= 10pq
(iii) 7l², – 3n²
= 7 × l² × (- 3) × n²
= 7 × (- 3) × l² × n²
= – 21l²n²
(iv) 6m, 3n
= 6 × m × 3 × n
= 6 × 3 × m × n
= 18 mn
(v) – 5x², – 2x
= (- 5) × x² × (- 2) × x
= (- 5) × (- 2) × x² × x
= 10x³

RBSE Solutions

Question 2.
Complete the table.

X 7 x y 2z a -5b c
7 49
x
2y
-3a -3ay
b
y
2x3
a4 a5
z2

Solution

X 7 x y 2z a -5b c
7 49 7x 7y 14z 7a -35b 7c
x 7x x2 xy 2zx ax -5bx cx
2y 14y 2xy 2y2 4yz 2ay -10by 2cy
-3a -21a -3ax -3ay -6az -3a2 15ab -3ac
b 7b bx by 2bz ab -5b2 bc
y 7y xy y2 2yz ay -5by cy
2x3 143 2x4 2x3y 4x3z 2x3a -10x3b 2x3c
a4 7a4 a4x a4y 2a4z a5 -5a4b a4c
z2 7z2 xz2 yz2 2z3 az2 -5bz2 cz2

RBSE Solutions

Question 3.
Multiply the following monomials
(i) xy, x²y, xy, x
(ii) m, n, mn, m3n, mn3
(iii) kl, lm, km, klm
Solution
(i) xy, x²y, xy, x
xy × x²y × xy × x
= x × y × x × x × y × x × y × x
= x × x × x × x × x × y × y × y
= x5 × y3
= x5y3
(ii) m, n, mn, m3n, mn3
m × n × mn × m3n × mn3
= m × n × m × n × m × m × m × n ×m × n × n × n
= m × m × m × m × m × m × n × n × n × n × n × n
= m6 × n6
= m6n6
(iii) kl, lm, km, klm
kl × lm × km × klm
= k × l × l × m × k × m × k × l × m
= k × k × k × l × l × l × m × m × m
= k3 × l3 × m3
= k3l3 × m3
= k3l3m3

RBSE Solutions

Question 4.
Find the simple interest = \(\frac { PTR }{ 100 }\), If principal (P) = 4x², time (T) = 5x and rate of interest (R) = 5y.
Solution
Simple Interest = \(\frac { PTR }{ 100 }\)
RBSE Solutions for Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1 img-1

RBSE Solutions

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