RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.4

RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.4 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.4.

Board RBSE
Class Class 9
Subject Maths
Chapter Chapter 8
Chapter Name Construction of Triangles
Exercise Ex 8.4
Number of Questions Solved 3
Category RBSE Solutions

Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.4

Question 1.
Construct a right-angled triangle the length (RBSESolutions.com)of whose hypotenuse is 5 cm and one of the remaining side is 3 cm long.
Solution.
Steps of construction:

  1. Draw a line segment AB = 3 cm.
  2. Take A as a centre, draw an angle of 90° by ruler and compass.
  3. Join angle line.
    RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.4
  4. Take B as centre, draw an arc of radius 5 cm which cuts the angle line (RBSESolutions.com)at the point C. Join BC.
    Hence, ∆ABC is required right-angled triangle.

RBSE Solutions

Question 2.
Construct a triangle ABC when ∠A = 90°, AC = 5.4 cm and hypotenuse BC = 10 cm.
Solution.
Steps of construction:

  1. Draw a line segment AC = 5.4 cm.
    RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.4
  2. Take A as centre, draw an angle of 90° by (RBSESolutions.com)ruler and compass.
  3. Take C as centre and draw an arc of radius 10 cm which intersects the angle line at B.
  4. Join B to C.
    Hence, ∆ABC is the required right angled triangle.

Question 3.
Construct a right angled triangle ABC whose ∠A = 90° and a = 10 cm and c = 6 cm, from the vertex A, draw a perpendicular on the hypotenuse.
Solution.
Steps of construction:

  1. Draw a line segment AB = 6 cm as base.
    RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.4
  2. With A as centre, draw an angle of 90°.
  3. With B as centre, draw an arc of radius 10 cm which (RBSESolutions.com)intersects the angle line at C.
  4. Again A as centre, draw perpendicular bisector of BC.
    Hence, ∆ABC is the required right angled triangle.

RBSE Solutions

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